8x^2=18(252)

Solution for 8x^2=18(252) equation:

8x^2=18(252)

We move all terms to the left:

8x^2-(18(252))=0

determiningTheFunctionDomain
8x^2-18252=0

a = 8; b = 0; c = -18252;
Δ = b2-4ac
Δ = 02-4·8·(-18252)
Δ = 584064
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{584064}=\sqrt{97344*6}=\sqrt{97344}*\sqrt{6}=312\sqrt{6}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-312\sqrt{6}}{2*8}=\frac{0-312\sqrt{6}}{16}
=-\frac{312\sqrt{6}}{16}
=-\frac{39\sqrt{6}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+312\sqrt{6}}{2*8}=\frac{0+312\sqrt{6}}{16}
=\frac{312\sqrt{6}}{16}
=\frac{39\sqrt{6}}{2}
$